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Section 13.2 Lagrange Kinematic Formula

The following formula is pivotal to the Lagrange formulation.

Proof.

We seek to find the scalar quantity \(\ba_P \cdot \frac{\partial \br_{OP}}{\partial q_i}\) for a given coordinate \(q_i\text{.}\) Here \(P\) represents an arbitrary point of the system. By using (13.1.3) we find
\begin{equation*} \ba_P \cdot \frac{\partial \br_{OP}}{\partial q_i} =\ba_P \cdot \frac{\partial \vel_P}{\partial \dq_i} = \frac{d}{dt}\left(\vel_P \cdot \frac{\partial \vel_P}{\partial \dq_i} \right) - \vel_P \cdot\frac{d}{dt}\left( \frac{\partial \br_{OP}}{\partial q_i} \right) \end{equation*}
The first term can be written as
\begin{equation*} \frac{d}{dt}\left(\vel_P \cdot \frac{\partial \vel_P}{\partial \dq_i} \right) =\tfrac{1}{2}\frac{d}{dt}\left(\frac{\partial \vel_P^2}{\partial \dq_i}\right) \end{equation*}
As for the second term, we cannot permute the operators \(\frac{d}{dt}\) and \(\frac{\partial}{\partial q_i}\text{:}\) as we did for equation (13.1.1) we consider \(\frac{\partial \br_{OP}}{\partial q_i}\) as a function of \((\bq, t)\) to find
\begin{align*} \frac{d}{dt}\left( \frac{\partial \br_{OP}}{\partial q_i} \right) \amp = \sum_{j=1}^n \frac{\partial^2 \br_{OP}}{\partial q_j\partial q_i} \, \dq_j + \frac{\partial^2 \br_{OP}}{\partial t\partial q_i} = \frac{\partial}{\partial q_i}\left(\sum_{j=1}^n \frac{\partial \br_{OP}}{\partial q_j} \, \dq_j + \frac{\partial \br_{OP}}{\partial t} \right)\\ \amp =\frac{\partial \vel_P}{\partial q_i} \end{align*}
Now we can write \(\vel_P \cdot\frac{d}{dt}\left( \frac{\partial \br_{OP}}{\partial q_i} \right)\) as \(\tfrac{1}{2} \frac{\partial}{\partial q_i} \vel_P^2\text{.}\)