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Problems 10.6 Problems

1.

Planets assume the shape of oblate spheroids due to their rotation. This shape is characterized by a flattening ratio \(f = (R_E - R_P)/R_E\text{,}\) defined as the ratio of the equatorial-polar radius difference \((R_E-R_P)\) to the equatorial radius \(R_E\text{.}\) The goal of this problem is to derive an expression for the gravitational field \(\bG_\Sigma\) created by such a body \(\Sigma\) of mass center \(O\text{,}\) mass \(M\text{,}\) equatorial plane \(Oxy\text{,}\) and polar axis \(Oz\text{.}\)
Figure 10.6.1.
  1. With reference to the figure, show that the gravitational field \(\bG_\Sigma (P)\) at a point \(P\) of position \(\br\equiv \br_{OP} = r\be_r\) is given by
    \begin{equation*} \bG_\Sigma (P) = -{G \over r^2} \be_r \int_\Sigma \left[ 1 - \frac{3}{2r^2} (\bs^2 -5 (\bs\cdot\be_r)^2 ) \right] \, dm + {3G \over r^4} \int_{\Sigma} (\bs\cdot\be_r) \bs \, dm \end{equation*}
    assuming that the distance \(r \equiv | \br_{OP}|\) from \(P\) to \(O\) is much larger than the distance \(|\bs|\) from any point \(Q\) of \(\Sigma\) to \(O\) (use the expansion \((1+x)^{-3/2} = 1 -3x/2 +15x^2 /8 + \cdots\))
  2. Show that \(\bG_\Sigma\) is given by the expression
    \begin{equation*} \bG_\Sigma (P) = - {G M \over r^2} \be_r + {3G \over 2r^4} (A-C) \left[ (1-3\sin^2 \phi)\be_r + 2 \sin\phi\cos\phi \be_\phi \right] \end{equation*}
    in terms of the coordinates \((r, \phi)\) of point \(P\text{,}\) and of the equatorial and polar moments of inertia \(A = I_{Ox} = I_{Oy}\) and \(C = I_{Oz}\text{.}\)
  3. Deduce that the gravitational field can be expressed in terms of potential \(\pot\text{,}\) that is
    \begin{equation*} \bG_\Sigma (P) = -\nabla \pot, \qquad \pot= - {G M \over r} + {G \over 2r^3} (C-A) (3\sin^2\phi -1) \end{equation*}
    with \(\nabla = - \be_r \partial / \partial r - \be_\phi \partial / r\partial\phi\text{.}\) Assuming that the free surface of \(\Sigma\) is a surface of equipotential, show that the flattening ratio \(f\) takes the expression
    \begin{equation*} f = \frac{3}{2} \frac{(C-A)}{MR_E^2} \end{equation*}
    (The value of \(f\) can range from 1/300 for Earth to 1/10 for Saturn).

2.

Consider the small-body approximation of Example 10.2.6. Show that the gravitational effect of Earth \(\cE\) (of mass \(M\text{,}\) and mass center \(C\text{.}\) modeled as a spherical body with material symmetry on a satellite \(\cS\) (of mass \(m\text{,}\) and mass center \(G\) can be approximated as
\begin{equation*} \{\cA^g_{\cE \to \cS}\} = - {G Mm \over \rho^2} \left\{ \begin{array}{c} \bx \\ \\ {3 \over m\rho} \Big[ (B-C) c_y c_z \bx_s + (C-A) c_x c_z \by_s +(A-B) c_x c_y \bz_s \Big] \end{array} \right\}_G \end{equation*}
where \((\bx_s,\by_s,\bz_s)\) is a principal basis of inertia of \(\cS\text{,}\) \((A,B,C)\) the corresponding principal moments of inertia, and \((c_x , c_y, c_z)\) are the direction cosines of \(\bx = \br_{CG}/\rho\) (with \(\rho= |CG|\)0) on \((\bx_s,\by_s,\bz_s)\text{:}\) \(\bx = c_x\bx_s +c_y\by_s+c_z\bz_s\text{.}\) To derive this result, assume that \(\br \equiv \br_{GP}\) is much smaller in magnitude than \(\rho\) for any point \(P\) of \(\cS\text{.}\)
Figure 10.6.2.

3.

Two bodies \(\cB_1\) and \(\cB_2\) are in relative rotation about the same axis \(\Delta\text{.}\) Body \(\cB_1\) is being pressed against \(\cB_2\) by an axial force \(P\) as shown, so that two conical surfaces characterized by kinetic friction coefficient \(\mu\) remain in contact.
Figure 10.6.3.
Find the contact action screw \(\{ \cA_{\cB_1 \to \cB_2}^c \}\) in terms of \(P\text{,}\) \(\mu\) and the geometrical parameters \(r_1\text{,}\) \(r_2\) and \(\theta\text{.}\)
Deduce that the maximum torque which can be transmitted from \(\cB_1\) to \(\cB_2\) without relative slip between the two contacting surfaces is given by
\begin{equation*} \cC_{\max{}} = {2\mu P \over 3 \sin\theta} {r_2^3 -r_1^3\over r_2^2 -r_1^2} \end{equation*}

4.

Consider the kinematic pair formed by the contact of two toroidal surfaces of bodies \(\cB_1\) and \(\cB_2\text{.}\) Assume that the contact is frictionless, that is, the surface force density is directed along the local unit normal to the surface of contact.
Show that the resulting contact action screw \(\{ \cA^c_{\cB_1 \to \cB_2} \}\) satisfies
\begin{equation*} \bz \cdot \bM^c_{O, 1\to 2} = 0 \end{equation*}
where point \(O\) is the common center of the tori.
Figure 10.6.4.