INSTRUCTOR: Dr. Ajay K. Prasad, 228 SPL
1994
a = 0, i.e., the nozzle is blocked and no flow is allowed.
a = A/2
a = A
Answer: (i) h = H; (ii) h = 0.75H; (iii) h = 0
You are required to form the dimensional matrix, find its rank, determine the correct number of Pi's, determine those Pi's, and then rewrite the relation u = f(y, tau_w, rho, mu) in dimensionless form.
Answer: u/sqrt(tau_w/rho) = F(u y rho /mu)
(i) Determine the expression for the exit velocity, u_1 = f(y).
(ii) Next, determine the drag force (per unit depth into the page) on the object, given that the pressure difference (P_0 - P_1) = 3 kPa. You may neglect friction between the walls and the water.
Hint: Since the problem is symmetric about the center line, you may work with only the upper half of the channel width (0 < y < 1 m).
Answer: u_1 = 4y; Drag on object = 3.33 kN/m (acting to right)
Answer: V_m = 2 m/s; Drag ratio = 36^3
u = U ( 2y/ax - y^2/a^2 x^2)
where a is a constant. Derive, from continuity the velocity component v(x,y) assuming that v=0 at the wall (y=0).
Answer: v = U (y^2/(a x^2) - 2 y^3/(3 a^2 x^3) )
1995
At what air speed should the model test be run?
With all similarity conditions satisfied, the measured drag on the model was determined to be 170 N. What is the predicted drag on the prototype dish?
Answer: V_m = 400 km/hr; D_m = D_p = 170 N
How many Pi's exist for this problem?
Determine the Pi's.
Answer: Q/sqrt(g d^5) = F(h/d, rho_g/rho_a)
Determine the horizontal component of the force exerted by the jet on the vane.
Determine the vertical component of the force exerted by the jet on the vane.
Answer: Horizontal force = 14.37 N (acting to right)
Vertical force = 3.85 N (acting up)
Answer: Q = 0.0133 m^3/s
u = 2xy
You are told that the flow is two-directional (only u and v are non-zero). You are also told (i) that the flow satisfies continuity, and (ii) that it is irrotational (i.e., vorticity is zero).
Determine v as a function of x and y.
Answer: v = x^2 - y^2 + const.
1996
Determine the drag force on the prototype.
Determine the power in kilowatts required to overcome the drag force on the prototype.
Answer: Drag = 350 N; Power = 4.86 kW
Using r, R, F and E (elastic modulus) form the dimensional matrix. What is the rank of this matrix? (rank = size of largest non-zero determinant).
How many Pi's exist in this system? What are they?
It is known that r varies as F^{1/3}. How then does r vary with R?
Answer: Two Pi's; r/R = F(F/ER^2); r ~ R^{1/3}
Answer: p = - rho C^2/2 ( x^2 + y^2) + const.
Answer: F = 692 N (acting to left)
What is the force F in newtons required to hold the cone fixed?
How does this force vary with the base diameter?
Answer: F = 11.35 N acting to left; F is independent of base diameter D, it depends on theta only.
1997
A transparent Plexiglas model is to be constructed to visualize the flow using water as the working fluid. Because this problem involves an open fluid surface, surface waves will be present; surface tension is also significant.
Write down the two non-dimensional groups that should be matched between model and prototype to ensure dynamic similarity.
What is the ratio, S, between the length scales of the prototype and the model?
Properties for water: rho = 1000 kg/m^3; gamma = 0.0073 N/m
Properties
for molten steel: rho = 7080 kg/m^3; gamma = 1.6 N/m
Answer: Match Froude and Weber numbers.
S = 5.56
From the given list of physical parameters, form the dimensional matrix and determine its rank. How many Pi's exist in this system?
It seems logical that the mass flux mdot is directly proportional to the width of the weir b. If so, how does mdot vary with h?
Answer: 2 Pi's: b/h and mdot^2/(rho^2 g h^5)
mdot ~ h^3/2
Answer: 2880 N
What are the pressures at sections 1 and 2?
What is the power added to the air by the fan?
What is the force required to hold the duct in place?
Answer: p_1 = -60 Pa; p_2 = 900 Pa;
Power = 30.16 kW
F =
1320 N (acting to right)
Assume that the fluid is incompressible, the flow is one-directional, one-dimensional, and steady. The flow is driven purely by the motion of the upper plate, i.e. all pressure gradients are zero.
Apply the Navier-Stokes equations to the coordinate system shown in the figure. Reduce it to a simple ODE (provide reasons for each simplification!). Solve the ODE with appropriate boundary conditions.
Derive an expression for the velocity profile, u = f(y).
What is the shear stress across the fluid?
Answer: u = U_o/h * y;
shear stress = mu U_o/h